[tex]\begin{gathered} \frac{1}{5}x^2+2=\frac{3}{5}x^2 \\ 2=\frac{3}{5}x^2-\frac{1}{5}x^2(\text{Subtracting }\frac{1}{5}x^2\text{ on both sides of the equation)} \\ 2=\text{ }\frac{2}{5}x^2\text{ (Subtracting)} \\ 2\cdot5=\text{ 2}x^2\text{ (Multiplying by 5 on both sides of the equation)} \\ 10/2=\text{ }x^2\text{ (Dividing by 2 on both sides of the equation)} \\ 5=x^2\text{ (Dividing)} \\ \pm\sqrt[]{5}=x\text{ (Taking the square root on both sides of the equation)} \\ \text{The solutions are x=}\sqrt[]{5}\text{ and x=}-\sqrt[]{5}\text{ } \end{gathered}[/tex]
