Respuesta :
Exlanation:
Solid iron(III) oxide reacts with hydrogen gas to form iron and water. The balanced equation of our reaction is:
Fe₂O₃ + 3 H₂ ----> 2 Fe + 3 H₂O
First we have to convert the mass of iron (III) oxide to moles. We can use the molar mass of Fe₂O₃ to do that.
molar mass of Fe₂O₃ = 159.69 g/mol
moles of Fe₂O₃ = 325.79 g * 1 mol/(159.69 g)
moles of Fe₂O₃ = 2.0401 moles
Fe₂O₃ + 3 H₂ ----> 2 Fe + 3 H₂O
According to the coefficients of the reaction 1 mol of Fe₂O₃ will react with 3 moles of H₂ to give 2 moles of Fe and 3 moles of H₂O. The molar ratio between is Fe₂O₃ and Fe is 1 to 2. We can use that relationship to find the number of moles of iron that are produced.
1 mol of Fe₂O₃ : 2 moles of Fe
moles of Fe = 2.0401 mles of Fe₂O₃ * 2 moles of fFe/(1 mol of Fe₂O₃)
moles of Fe = 4.0802 moles
And finally we can convert those moles into grams using the molar mass of Fe.
molar mas of Fe = 55.85 g/mol
mass ofFe = 4.09802 moles * 55.85 g/mol
mas o f Fe = 227.88 g
227.88 g of iron are produced.
Answer:
