SOLUTION
The given terminal point is
[tex](\frac{\sqrt{3}}{2},\frac{1}{2})[/tex]
A terminal point is of the form:
[tex](\cos\theta,\sin\theta)[/tex]
It follows:
[tex]\cos\theta=\frac{\sqrt{3}}{2}[/tex]
This gives:
[tex]\begin{gathered} \theta=\cos^{-1}(\frac{\sqrt{3}}{2}) \\ \theta=30 \end{gathered}[/tex]
Therefore the answwer is 30 degrees
