Step 1: Find the Area of the given rectangle
[tex]\begin{gathered} A_{\text{rectangle}}=\text{length }\times width \\ \text{length}=90m;\text{ width= 50m} \\ A_{\text{rectangle}}=90m\times50m \\ =4500m^2 \end{gathered}[/tex]Step 2: Randomly give length and width that will have the same perimeter but a smaller area
[tex]\text{Let the new length be 100m and width be 40m}[/tex][tex]\begin{gathered} A_{\text{rectangle}}=100m\times40m \\ =4000m^2 \end{gathered}[/tex]Hence, the given new dimension is 40m wide and 100m long