Respuesta :

[tex]\begin{gathered} \theta=\frac{7\pi}{6} \\ 2\sin (\frac{7\pi}{6})=2(\frac{-1}{2})=-1 \\ 2\sin (\frac{7\pi}{6})=-1 \\ \\ \sin ^2(\frac{7\pi}{6})=(\frac{-1}{2})^2=\frac{1}{4} \\ \sin ^2(\frac{7\pi}{6})=\frac{1}{4} \\ \\ \sin (-\frac{7\pi}{6})=-\sin (\frac{7\pi}{6})=-(\frac{-1}{2})=\frac{1}{2} \\ \sin (-\frac{7\pi}{6})=\frac{1}{2} \end{gathered}[/tex]

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