The Solution:
Given the figure below:
Translating 3 units left and 4 units down of AVFC, we have the formula below:
[tex](x,y)\rightarrow(x-3,y-4)[/tex]
So, the required coordinates are:
[tex]A^{\prime}=(-1-3,1-4)=(-4,-3)[/tex][tex]V^{\prime}=(3-3,3-4)=(0,-1)[/tex][tex]F^{\prime}=(6-3,3-4)=(3,-1)[/tex][tex]C^{\prime}=(2-3,-2-4)=(-1,-6)[/tex]
