The direction of a vector given its coordinates (x, y) is :
[tex]\theta=\arctan (\frac{y}{x})[/tex]
If the vector is in Q1, θ
If in Q2, 180 - θ
If in Q3, 180 + θ
If in Q4, 360 - θ
From the problem, the coordinates of the vector is (-3, -10).
Solving for θ,
[tex]\begin{gathered} \theta=\arctan (\frac{-10}{-3}) \\ \theta=73.30 \end{gathered}[/tex]
Since the vector is in Q3, the direction will be :
[tex]180+73.30=253.30[/tex]
ANSWER :
253.30 degrees
