We are trying to figure out this answer so we can do the rest of our work.

We count the number of movements till we get to the first number
[tex]\begin{gathered} \text{The notation is in the form: } \\ a\text{ }\times10^{number\text{ of movement}} \\ \text{first number = 1} \\ \end{gathered}[/tex][tex]\begin{gathered} nu\text{mber of movement from the right to the first number:} \\ =\text{ 8} \end{gathered}[/tex][tex]\begin{gathered} A\text{ decimal point is place in front of the 1st number:} \\ 1.73700000\text{ }\times10^8 \\ =\text{ 1.737 }\times10^8\text{ cm} \end{gathered}[/tex]