Answer:
The correct unit for V0 is feet per second
Explanation:
We can solve for V0 as:
[tex]\begin{gathered} d=\frac{V^2_0}{2g(f+G)} \\ d\cdot(2g(f+G))=V^2_0 \\ \sqrt[]{2dg(f+G)}=V_0 \end{gathered}[/tex]
o, if the unit of d is feet, the unit g is ft/s², and f and G don't have units, we get that the unit of V0 is:
[tex]\begin{gathered} \sqrt[]{ft\cdot\frac{ft}{s^2}}=V_0 \\ \sqrt[]{\frac{ft^2}{s^2}}=V_0 \\ \frac{ft}{s}=V_0_{} \end{gathered}[/tex]
Therefore, the correct unit for V0 is ft/s or feet per second
