This can be solve easily by taking ratios.
We can say:
5 1/2 feet casts 9 feet shadow, so
HOW MANY FEET (let it be x) will cast 30 feet shadow??
We can setup a ratio with this info:
[tex]\frac{5.5}{9}=\frac{x}{30}[/tex]Note: We took 5 1/2 feet as 5.5 feet (decimal)
Now, we cross multiply and solve for x:
[tex]\begin{gathered} \frac{5.5}{9}=\frac{x}{30} \\ 9x=5.5\times30 \\ 9x=165 \\ x=\frac{165}{9} \\ x=18\frac{1}{3}ft \end{gathered}[/tex]The utility pole is 18 1/3rd feet.
