(i) The balanced equation will be as follows:
[tex]2Br_2(aq)+C\text{ }(s)\Rightarrow\text{ CBr}_4(s)\text{ }[/tex](ii) Determine Moles of Bromine
• Molecular mass Bromine =79,904 g/mol
,• Mass of Bromine = 8 g
[tex]\begin{gathered} Moles\text{ = Mass/ molecular mass } \\ \text{ = 8g /79.904g.mol}^{-1} \\ \text{ = 0.1 moles of bromine } \end{gathered}[/tex](iii) Determine moles of Carbon tetrabromide :
By stoichiometry, we can determine that :
• 2 moles bromine produces 1 mole CBr4
,• 0.1 mole bromine will produce X moles CBr4
Therefore , moles of CBr4 = (0.1 mole Br * 1 mole CBr4 )/2 moles Br
= 0.05 moles
(iv) Calculate mass of CBr4
• moles of CBr4 = 0.05moles
• Molecular mass CBr4 =331,63 g/mol
Therefore , Mass of CBr4 is
[tex]\begin{gathered} Mass\text{ = moles * molecular mass } \\ \text{ = 0.05 mol* 331.63g/mol} \\ \text{ =16.58 grams } \end{gathered}[/tex]