In this case it is convinient to transform first 2 1/2 into an improper fraction
[tex]2\frac{1}{2}=\frac{4}{2}+\frac{1}{2}=\frac{5}{2}[/tex]And the equation becomes in
[tex]\frac{2}{3}(n-\frac{5}{6})=\frac{5}{2}[/tex]Since all the denominators are divisible by 6, it is convinient to multipy all the equation by
[tex]\begin{gathered} \frac{6\times2}{3}(n-\frac{5}{6})=\frac{5\times6}{2} \\ 4(n-\frac{5}{6})=15 \\ 4n-\frac{4\times5}{6}=15 \\ 4n-\frac{10}{3}=15 \\ 12n-10=45 \\ 12n=55 \\ n=\frac{55}{12} \\ n=4\text{ }\frac{7}{12} \end{gathered}[/tex]Then, the answer ic C.) 4 7/12