Respuesta :
From the equation of reaction, 2 moles of O₂ reacted to produce N₂O₄.
Using moles-mass-molar mass relationship
[tex]\begin{gathered} n=\frac{mass}{molar\text{ mass}} \\ \end{gathered}[/tex]Let's find the mass of O₂ in the equation of reaction.
[tex]\begin{gathered} n=\frac{\text{mass}}{\text{molar mass}} \\ 2=\frac{\text{mass}}{16} \\ \text{mass}=32g \end{gathered}[/tex]Mass of N₂O₄ in the equation of reaction.
[tex]\begin{gathered} n=\frac{\text{mass}}{\text{molar mass}} \\ 1=\frac{\text{mass}}{92} \\ \text{mass = 92g} \end{gathered}[/tex]from the calculation above, 32g of O₂ produce 92g of N₂O₄
x g of O₂ will produce 47.6g of N₂O₄
cross multiply both sides and make x the subject of formula.
[tex]\begin{gathered} x=\frac{32\times47.6}{92} \\ x=16.56g \end{gathered}[/tex]From the calculations above, 16.56g of O₂ will produce 47.6g of N₂O₄.
