[tex]\text{ANSWER: }\sum ^{10}_{i\mathop{=}1}(x_i-46)=\text{ }-661[/tex]
From the given question:
[tex]x_{1\text{ }}=\text{ -76, }x_{2\text{ }}=\text{ -}85,\text{ }x_{3\text{ }}=13,\text{ }x_{4\text{ }}=\text{ -}29,\text{ }x_{5\text{ }}=\text{ 89, }[/tex][tex]x_{6\text{ }}=\text{ -}65,\text{ }x_{7\text{ }}=\text{ 3, }x_{8\text{ }}=64,\text{ }x_{9\text{ }}=\text{ -}81,\text{ }x_{10\text{ }}=\text{ -35}[/tex][tex]\sum ^{10}_{i\mathop=1}(x_i-46)=(x_{1-}46)\text{ + }(x_{2-}46)\text{ + }(x_{3-}46)+\cdots+(x_{10-}46)[/tex][tex]\sum ^{10}_{i\mathop=1}(x_{1-}46)\text{ = }[/tex]
(-76-46) + (-85-46) + (13-46) + (-29-46) + (89-46) + (-65-46) + (3-46) + (64-46) + (-81-46) + (-35-46)
[tex]\sum ^{10}_{i\mathop=1}(x_i-46)\text{ = }-122\text{ - }131-33-75\text{ + 43}-111-43\text{ + 18 - 127 - }81[/tex][tex]\sum ^{10}_{i\mathop{=}1}(x_i-46)=\text{ }-661[/tex]
