Given the inequality:
[tex]-6x\ge-6y+54[/tex]
Divide all through by 6:
[tex]\begin{gathered} \frac{-6x}{6}\ge\frac{-6y}{6}+\frac{54}{6} \\ -x\ge-y+9 \end{gathered}[/tex]
(a)The inequality sign is greater than or equal to, therefore, the boundary line is solid.
(b)Next, we draw the boundary line using the boundary line equation: -x=-y+9
[tex]\begin{gathered} \text{When }x=0,-0=-y+9\implies y=9\implies(0,9) \\ \text{When y}=0,-x=0+9\implies x=-9\implies(-9,0) \end{gathered}[/tex]
Two points on the boundary line are (0,9) and (-9,0).
(c)The graph is attached below:
Note: To determine
