We have the formula of the slope given two points
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]where m is the slope and (x1,y1) , (x2,y2) are the points given
in our case we have
(-41.28,4.8) =(x1,y1)
(2.28,3.2)=(x2,y2)
We substitute the values
[tex]m=\frac{3.2-4.8}{2.2+41.28}=-0.0367[/tex]