Solution
Probability = number of required outcome / number of possible outcome
Transfer student = 10
nursing students = 7
AAS students = 4
Undecided = 1
Total = 22
If three students are chose randomly, without replacement,
[tex]\begin{gathered} Pr(\text{transfer student) = }\frac{10}{22} \\ \text{and} \\ Pr(AASstudent)=\frac{4}{21} \\ \text{and } \\ Pr(\text{Undecided) }=\frac{1}{20} \end{gathered}[/tex][tex]\begin{gathered} Pr(\text{selecting 3 student) =}\frac{10}{22}\times\frac{4}{21}\times\frac{1}{20} \\ P(\text{selecting 3 student) = }\frac{1}{231} \end{gathered}[/tex]Therefore the probability = 1/231