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8.On a frictionless air track, a 0.15 kg glider moving to the right collides with and sticks to a stationary0.25 kg glider. The net momentum of this system after the collision is 0.18 kg. m/s. What is thespeed of the gliders after the collision?0.45 m/s0.97 m/s0.66 m/s1.32 m/s

Respuesta :

We have the next information

m1=0.15kg

m2=0.25 kg

First, we need to sum the masses

[tex]m=m1+m1=0.15+0.25=0.4[/tex]

then the momentum formula is

[tex]p=m\cdot v[/tex]

where p is the momentum, m is the mass and v is the speed

[tex]0.18=0.4\cdot v[/tex]

then we isolate v

[tex]v=\frac{0.18}{0.4}=0.45\text{ m/s}[/tex]

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