Given:
|x + 2| < 2
Let's solve for x.
Given the absolute value, we have 2 conditions. They are:
x + 2 < 2 and x + 2 > -2
Let's find x for both conditions.
Condition 1:
x + 2 < 2
Subtract 2 from both sides:
x + 2 - 2 < 2 - 2
x < 0
Condition 2:
x + 2 > -2
Subtract 2 from both sides:
x + 2 - 2 > -2 - 2
x > -4
Therefore,
x < 0 and x > -4
In interval notation, we have the solution as:
(-4, 0)
The graph of the inequality is below:
