We have the line in standard form:
[tex]4x+5y=-20[/tex]
We have to find the 2 intercepts.
The y-intercept correspond to the value of the line when x=0, so we can find the value of y that correspond to x=0 replacing x in the equation and solving for y:
[tex]\begin{gathered} 4x+5y=-20 \\ 4(0)+5y=-20 \\ 5y=-20 \\ y=-\frac{20}{5} \\ y=-4 \end{gathered}[/tex]
Then, the ordered pair for the y-intercept is (0,-4).
In the case of the x-intercept the concept is equivalent but the coordinate that has a value of 0 is y. So we will replace y with 0 in the equation and solve for x:
[tex]\begin{gathered} 4x+5(0)=-20 \\ 4x=-20 \\ x=-\frac{20}{4} \\ x=-5 \end{gathered}[/tex]
Then, the ordered pair for the x-intercept is (-5,0).
We can graph the line and its intercepts as:
Answer:
X-intercept: (-5, 0)
Y-intercept: (0,-4)
