Given:
The resistance is,
[tex]R=200\text{ ohm}[/tex]The capacitance is,
[tex]\begin{gathered} C=25\text{ mF} \\ =25\times10^{-3}\text{ F} \end{gathered}[/tex]The applied voltage is,
[tex]V=120\text{ V}[/tex]The frequency of the AC is,
[tex]f=60\text{ Hz}[/tex]To find:
The capacitive reactance
Explanation:
The capacitive reactance is,
[tex]\begin{gathered} X_C=\frac{1}{2\pi fC} \\ =\frac{1}{2\pi\times60\times25\times10^{-3}} \\ =0.106\text{ ohm} \end{gathered}[/tex]Hence, the capacitive reactance is 0.106 ohm.
