Respuesta :

Given:

[tex]v=520\sin (30t-\frac{5\pi}{4})[/tex]

We know that:

[tex]-1\le\sin \theta\le1[/tex]

So the peak voltage can be calculated using the maximum value of the sine function (1 in this case). Then:

[tex]v_{\text{peak}}=520\cdot1=520[/tex]

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