In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
H = 4
G = 0.25
Step 02:
inverse variation:
y = k / x
[tex]G=\frac{k}{H^2}[/tex]H = 4 and G = 0.25:
k:
[tex]\begin{gathered} 0.25=\frac{k}{4^2} \\ \\ 0.25=\frac{k}{16} \\ \\ 16*0.25=k \\ \\ 4\text{ = k} \end{gathered}[/tex]H = 0.3, G:
[tex]G=\frac{k}{H^2}=\frac{4}{0.3^2}=\frac{4}{0.09}=44.4[/tex]The answer is:
G = 44.4
