Explanation
Given
N2(g)+3H2(g)—> 2NH3(g)
Number of moles of nitrogen = 1.5 moles
Number of moles of hydrogen = 6 moles
Required: Limiting reagent
Solution
For Nitrogen:
[tex]\begin{gathered} 1,5\text{ mol N x }\frac{2\text{ mol NH}_3}{1\text{ mol N}_2} \\ \\ Moles\text{ of NH}_3=3\text{ mol} \end{gathered}[/tex]For Hydrogen:
[tex]\begin{gathered} 6\text{ mol H x }\frac{2\text{ mol NH}_3}{3\text{ mol H}_2} \\ \\ Moles\text{ of NH}_3=\text{ 4 mol} \end{gathered}[/tex]The limiting reagent is Nitrogen, because less moles of NH3 will be produced by nitrogen, meaning it all of it gets used up.
Answer
The limiting reagent is Nitrogen.
