First, find the probability of choosing a married man among the 8 men.
Since there are 3 married couples, then there are 3 married men among the 8 men. Then, the probability of choosing a married man is:
[tex]\frac{3}{8}[/tex]On the other hand, only 1 among the group of 4 women is the wife of the previously chosen married man. The probability of picking the wife of that man is:
[tex]\frac{1}{4}[/tex]The probability of both events happening one after another is the product of the individual probabilities of choosing a married man and choosing that man's wife. Then, the probability that a married couple gets selected, is:
[tex]\frac{3}{8}\times\frac{1}{4}=\frac{3}{32}[/tex]Therefore, the answer is: 3/32.
