Let's begin by listing out the given information:
An electric clock has 60 equal intervals (seconds)
Between the 3 and 4, there are 5 equal intervals (seconds)
The probability that the second hand stops between the 3 and 4 is:
[tex]\begin{gathered} P=\frac{5}{60}=\frac{1}{12} \\ P=\frac{1}{12} \end{gathered}[/tex]