Given:
The number of people who does not drive the red car is 475.
The number of people who got s speeding tickets is 87.
The number of person does not drive a red car and got a speeding ticket is 39.
Total number of people is 949.
To find the probability that the person does not drive a red car or got a speeding ticket is,
[tex]\begin{gathered} P(\text{ Does not drive car or speeding ticket)=P(R)}+P(S)-P(R\text{ and S)} \\ =\frac{475}{949}+\frac{87}{949}-\frac{39}{949} \\ =\frac{475+87-39}{949} \\ =\frac{523}{949} \\ =0.5511 \end{gathered}[/tex]
Answer: probability is 0.5511.