Respuesta :
Given:
The magnitude of the magnetic field is,
[tex]\begin{gathered} B=22.537\text{ }\mu T \\ =22.537\times10^{-6}\text{ T} \end{gathered}[/tex]The current in the wire is,
[tex]i=73.298\text{ A}[/tex]To find:
The distance from the wire to that location
Explanation:
The magnetic field due to a current-carrying wire at a distance 'r' is,
[tex]B=\frac{\mu_0i}{2\pi r}[/tex]Here,
[tex]\mu_0=4\pi\times10^{-7}\text{ H/m}[/tex]Substituting the values we get,
[tex]\begin{gathered} 22.537\times10^{-6}=\frac{4\pi\times10^{-7}\times73.298}{2\pi r} \\ r=\frac{4\pi\times10^{-7}\times73.298}{2\pi\times22.537\times10^{-6}} \\ r=0.65\text{ m} \end{gathered}[/tex]Hence, the required distance from the wire is 0.65 m.
