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The electric field between two parallel plates connected to a 45 V battery (which produces a 45 V difference in potential between the plates) is 1500 N/C. How far apart are the plates?

Respuesta :

ANSWER is 0.03m

[tex]d=\frac{v}{e}=\frac{45}{1500}=0.03[/tex]

where d is the distance between the plates, v is difference in potential between the plates, e is electric field.

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