So I need to know what is the probability that a randomly selected club member reads about 1 hour per week and prefers any paperback books?

First, find the total number of people that were surveyed,
[tex]T=6+3+2+6=17[/tex]Then, look for the cell in the table that corresponds to the intersection between 'Paperback books' and 'About 1 hour per week'. The number in such cell is 3; therefore, the probability we are looking for is
[tex]P(Paperback\cap1hour)=\frac{3}{T}=\frac{3}{17}[/tex]The answer is 3/17.