Let A and B be the following events:
[tex]\begin{gathered} A=\mleft\lbrace x>1\mright\rbrace \\ B=\mleft\lbrace x\ge2\mright\rbrace \end{gathered}[/tex]first, we can find the probability of event A:
[tex]\begin{gathered} P(x>1)=P(2)+P(3)+P(4)+P(5) \\ =0.19+0.13+0.31+0.04=0.67 \end{gathered}[/tex]then, the probability of event B is:
[tex]\begin{gathered} P(x\ge2)=P(2)+P(3)+P(4)+P(5) \\ =0.19+0.13+0.31+0.04=0.67 \end{gathered}[/tex]notice that both probabilities are the same, so, the events must be the same too. Therefore, P(A or B) = 0.67
