We will have the following:
We recall that the normal force is perpendicular to the surface, so we can see that in scenario A and scenario C the normal force will be a component of the weight of the car, and thus it will be less than the weight.
Free body diagrams:
Scenario A:
Scenario B:
Scenario C:
Scenario D:
***Equations for scenarios A and :***
Scenario A:
[tex]\begin{gathered} \sum F_x=Ncos(\theta) \\ \\ \sum F_y=wg+Nsin(\theta) \end{gathered}[/tex]
*Scenario C:
[tex]\begin{gathered} \sum F_x=Fcos(\theta) \\ \\ \sum F_y=mg+N+Fsin(\theta) \end{gathered}[/tex]
