Given:
Height, h = 20 m
Mass of block, m = 10 kg
Velocity, v = 34.29 m/s
Let's find the kinetic energy and the potential energy of the block.
• Kinetic energy.
To find the kinetic energy, apply the formula:
[tex]KE=\frac{1}{2}mv^2[/tex]
Where:
m is the mass = 10 kg
v is the velocity = 34.29 m/s
Input values into the formula:
[tex]\begin{gathered} KE=\frac{1}{2}\times10\times34.29^2 \\ \\ KE=5879\text{ J }\approx5880\text{ J} \end{gathered}[/tex]
The kinetic energy is 5880 Joules.
• Potential Energy.
To find the potential energy, apply the formula:
[tex]PE=m\times g\times h[/tex]
Where:
m is the mass = 10 kg
g is acceleration due to gravity = 9.8 m/s²
h is the height = 20 m
Input values into the formula and solve:
[tex]\begin{gathered} PE=10\times9.8\times20 \\ \\ PE=1960\text{ J} \end{gathered}[/tex]
Therefore, the potential energy is 1960 Joules.
• Kinetic energy = 5880 J
,
• Potential energy = 1960 J.
ANSWER:
D. None of the above
