To solve this problem we can write one equation for each condition so:
the width of a rectangle is 2 its length so:
[tex]W=2L[/tex]and one for the perimeter so:
[tex]2W+2L=540[/tex]Now we replace the first equation into the second one so:
[tex]\begin{gathered} 2(2L)+2L=540 \\ 4L+2L=540 \\ 6L=540 \\ L=\frac{540}{6} \\ L=90 \end{gathered}[/tex]So the length of the rectangle is 90 ft
