Given the following equation:
[tex]6-2\mleft(x+6\mright)=3x+4[/tex]
You can solve it by following the steps shown below:
1. Apply the Distributive Property on the left side of the equation:
[tex]\begin{gathered} 6-(2)\mleft(x)-(2)(6\mright)=3x+4 \\ 6-2x-12=3x+4 \end{gathered}[/tex]
2. Apply the Addition Property of Equality by adding this term to both sides of the equation:
[tex]2x[/tex]
Then:
[tex]\begin{gathered} 6-2x-12+(2x)=3x+4+(2x) \\ 6-12=5x+4 \end{gathered}[/tex]
3. Solve the Subtraction on the left side of the equation:
[tex]-6=5x+4[/tex]
4. Apply the Subtraction Property of Equality by subtracting 4 from both sides of the equation.
[tex]\begin{gathered} -6-(4)=5x+4-(4) \\ -10=5x \end{gathered}[/tex]
5. Finally, you can apply the Division Property of Equality by dividing both sides of the equation by 5:
[tex]\begin{gathered} \frac{-10}{5}=\frac{5x}{5} \\ \\ -2=x \\ x=-2 \end{gathered}[/tex]
Therefore, the answer is:
[tex]x=-2[/tex]
