To simplify the calculations, first, we solve the given equation for y:
[tex]\begin{gathered} 2x=5y+10, \\ 2x-10=5y, \\ \frac{2}{5}x-2=y. \end{gathered}[/tex]
Now, we evaluate
[tex]y=\frac{2}{5}x-2,[/tex]
at x=0, and x=-5:
[tex]\begin{gathered} y=\frac{2}{5}(0)-2=-2, \\ y=\frac{2}{5}(-5)-2=-2-2=-4. \end{gathered}[/tex]
Now, solving the given equation for x, we get:
[tex]\begin{gathered} 2x=10+5y, \\ x=5+\frac{5}{2}x. \end{gathered}[/tex]
Evaluating the above equation at y=0, and y=2, we get:
[tex]\begin{gathered} x=5+\frac{5}{2}(0)=5, \\ x=5+\frac{5}{2}(2)=5+5=10. \end{gathered}[/tex]
Answer:
Table:
Graph:
