33. Three consecutiveintegers exist such that fivetimes the first number isequal to one more than twicethe sum of the second andthird numbers.Which equation accuratelysolves for the integers?Let n represent the firstnumber.

Answer:
5n=1+2(n+1+n+2)
Explanation:
Let the first number = n
Therefore, the three consecutive integers are n, n+1, and n+2.
• Five times the first number = 5n
One more than twice the sum of the second and third numbers.
• The sum of the second and third numbers = n+1+n+2
,• Twice the sum of the second and third numbers = 2(n+1+n+2)
• One more than twice the sum of the second and third numbers = 1+2(n+1+n+2)
Therefore, the equation that accurately solves for the integers is:
[tex]5n=1+2(n+1+n+2)[/tex]The last option is correct.