ShemarE447461 ShemarE447461

28-10-2022
Physics

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A ball is at rest on an inclined plane, as shown below. When it is released, what will its velocity be at the bottomof the ramp?

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KirklandX432950 KirklandX432950

28-10-2022

[tex]\begin{gathered} KE=PE \\ \frac{mv^2}{2}=mgh \\ \frac{v^2}{2}=gh \\ v=\sqrt{2gh} \\ v=\sqrt{2\cdot9.81m/s^2\cdot.55}m \\ v=3.28m/s \end{gathered}[/tex]

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