[tex]\frac{64mi}{h}(t)\text{ - }\frac{51mi}{h}(t)=517.5mi[/tex]
This would be the initial equation because, after a certain amount of t time, the fastest truck will be 517. mi apart from the slowest truck. Let's solve the equation
[tex]\begin{gathered} t(64mi/h\text{ - }51mi/h)=517.5mi \\ t(13mi/h)=517.5mi \\ t=\frac{517.5mi}{13mi/h} \\ \\ t=39.81h \end{gathered}[/tex]
After 39.81h the trucks will be apart 517.5 mi
