[tex]\begin{gathered} \text{if they are parallel then the slope for m is the same than for f.} \\ so\text{ we get that slope =5/11 and a point (-18,3) then} \\ y-3=\frac{5}{11}(x-(-18))=\frac{5}{11}(x+18) \\ y=\frac{5}{11}x+\frac{90}{11}-3=\frac{5}{11}x+\frac{57}{11} \end{gathered}[/tex]
