Given:
[tex]3x+y=4\ldots\ldots\ldots\ldots\text{ take it as equation (1).}[/tex][tex]6x+2y=8\ldots\ldots\ldots\ldots\text{ take it as equation (2).}[/tex]
Multiply both sides of the equation (1) by 2, we get
[tex](2)3x+(2)y=(2)4[/tex]
[tex]6x+2y=8\ldots\ldots\ldots\ldots\text{ take it as equation (3).}[/tex]
Subtract equation (2) from equation (3), we get
[tex](6x+2y)-(6x+2y)=8-8[/tex][tex]0=0[/tex]
We obtain equation (2) by multiplying 2 and equation (1).
Equation 2 is dependent on equation (1).
We know that a dependent system has an infinite number of solutions.
The solution of the system has many solutions.
