Answer:
The molarity of the solution is 0.19M. (first option)
Explanation:
The given information from the exercise is:
- Moles of NaCl (n): 0.65 moles
- Volume of solution (V): 3.50L
To calculate the molarity of the solution we have to replace the values of n and V in the Molarity formula:
[tex]\begin{gathered} M=\frac{n\text{ \lparen moles of solute\rparen}}{V(volume\text{ of solution})} \\ M=\frac{0.65moles}{3.50L} \\ M=0.19M \end{gathered}[/tex]
So, the molarity of the solution is 0.19M.
