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I got -3x^8 but i think i solved it wrong... i just divided 3 the radical to the exponent 24 and got 8 and then found what was multiplied 3 times it self into -27 then I got 3 square toot (-3x^8)^3 and the radical 3 divided out 3 and left me with -3x^8 but that doesn't make any sense. Can I have step by step guide?

I got 3x8 but i think i solved it wrong i just divided 3 the radical to the exponent 24 and got 8 and then found what was multiplied 3 times it self into 27 the class=

Respuesta :

Given:

[tex]\sqrt[3]{-27x^{24}}[/tex]

a)

Yes the expression is a perfect root because we can take a rrot as a real number.

b)

[tex]\sqrt[3]{-27x^{24}}=\sqrt[3]{-3^3\times x^{^8}\times x^{^8}\times x^{^8}}[/tex][tex]\sqrt[3]{-27x^{24}}=-3x^8[/tex]

c)

Simplified form is negative because cube root of negative is negative.

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