Let's solve the following system of equations
[tex]\begin{gathered} 3x+2y=26 \\ 3x-2y=10 \end{gathered}[/tex]Eq 1 + Eq 2
[tex]3x+2y+3x-2y=26+10[/tex][tex]6x=36[/tex][tex]x=6[/tex]Now for y
[tex]y=\frac{26-3x}{2}[/tex][tex]y=\frac{26-3\cdot6}{2}[/tex][tex]y=\frac{8}{2}[/tex][tex]y=4[/tex]