The perimeter of a rectangle is 130 ft.
Let x be the length of the rectangle and y be the width of the rectangle.
Then,
[tex]\begin{gathered} 2(x+y)=130 \\ x+y=65\ldots\ldots(1) \end{gathered}[/tex]Lenght is 9 feet shorter than width. Therefore,
[tex]x=y-9\ldots\ldots(2)[/tex]Put equation (2) in (1) implies,
[tex]\begin{gathered} y-9+y=65 \\ 2y=74 \\ y=37 \end{gathered}[/tex]Then, the value of x is ,
[tex]\begin{gathered} x=37-9 \\ x=28 \end{gathered}[/tex]Therefore, the dimensions are 28 and 37.
