A uniform electric field is established in the space within a parallel plate capacitor. Determine its magnitude if the plate separation is 3.60 cm and the capacitor is charged at a voltage of 62.00 V.

Respuesta :

The electric field on a capacitor is given by:

[tex]E=\frac{V}{d}[/tex]

where d is the distance between the plates and V is the voltage in the capacitor. In this case, the voltage is 62 V and the distance is 0.036 m; plugging these values we have:

[tex]E=\frac{62}{0.036}=1722.22[/tex]

Therefore, the electric field i 1722.322 V/m