Given,
The mass of the sled and the person, m=62.5 kg
The coefficient of the kinetic friction, μ=0.190
The harness tension, T=180.o N
From Newton's second law, the net force on the sled is given by,
[tex]F_n=ma[/tex]
the net force is also given by the sum of all the forces acting on it.
Thus,
[tex]\begin{gathered} F_n=ma=T-f \\ \Rightarrow ma=T-N\mu_{} \\ =T-mg\mu \end{gathered}[/tex]
Where f is the frictional force and g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} 62.5a=180.0-62.5\times9.8\times0.190 \\ a=\frac{180-62.5\times9.8\times0.190}{62.5} \\ =1.018\text{ m/s}^2 \end{gathered}[/tex]
Thus the acceleration of the sled is 1.018 m/s²
