Simplify the expression x^2+2x-8 to obtain the equation as complete square.
[tex]\begin{gathered} x^2+2x-8=x^2+2x+1-1-8 \\ =(x^2+2x+1)-9 \\ =(x+1)^2-9 \end{gathered}[/tex]
The value of square terms is 0 or postive, so range of the expression x^2+2x-8 is,
[tex]\lbrack-9,\infty)[/tex]
So correct option is B greater than or equal to -9.
