ANSWER
The length of the rectangle is 8 inches and its width is 3 inches.
EXPLANATION
Let the length of the rectangle be L.
Let the width of the rectangle be W.
The length of the rectangle is 5 inches more than the width. This implies that:
[tex]L=5+W[/tex]The perimeter of the rectangle is 22 inches. This implies that:
[tex]P=2(L+W)=22[/tex]Substitute the first equation into the second, we have:
[tex]\begin{gathered} 2(5+W+W)=22 \\ \Rightarrow2(5+2W)=22 \\ 10+4W=22 \\ \Rightarrow4W=22-10=12 \\ \Rightarrow W=\frac{12}{4} \\ W=3in \end{gathered}[/tex]Substitute the value of W into the equation for L:
[tex]\begin{gathered} L=5+3 \\ L=8in \end{gathered}[/tex]Therefore, the length of the rectangle is 8 inches and its width is 3 inches.
