part a. A penny falls, from rest, from a high window, and accelerates downwards because of gravity. How much time will pass before the velocity of the penny is -15.0 m/s? part b. How far will the penny have fallen at this time?

Given:
the penny falls from rest.
The final speed of the penny is,
[tex]v=-15.0\text{ m/s}[/tex]To find:
The time taken by the penny
the distance covered by the penny in this time
Explanation:
a)
Let, the time be t.
We can write,
[tex]v=u+gt[/tex]substituting the values we get,
[tex]\begin{gathered} -15.0=0-9.8\times t \\ t=\frac{15.0}{9.8} \\ t=1.53\text{ s} \end{gathered}[/tex]Hence, the required time is 1.53 s.
b)
In this time time the penny falls,
[tex]\begin{gathered} h=-\frac{1}{2}gt^2 \\ =-\frac{1}{2}\times9.8\times1.53^2 \\ =-11.5\text{ m} \end{gathered}[/tex]Hence, the penny had fallen 11.5 m downward.